0=5z^2-4z+5

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Solution for 0=5z^2-4z+5 equation:



0=5z^2-4z+5
We move all terms to the left:
0-(5z^2-4z+5)=0
We add all the numbers together, and all the variables
-(5z^2-4z+5)=0
We get rid of parentheses
-5z^2+4z-5=0
a = -5; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-5)·(-5)
Δ = -84
Delta is less than zero, so there is no solution for the equation

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